A capacitor holds 0.06 coulombs of charge when fully charged by a 9-volt battery. Calculate the capacitance of the capacitor. Ans. (6.67 𝐱10⁻³ F)
Given Data:
Charge on Capacitor = Q = 0.06 C
voltage = V = 9 V
Charge on Capacitor = Q = 0.06 C
voltage = V = 9 V
To Find:
Capacitance = C = ?
Solution:
We know thatQ = CV
or
C = `\frac{Q}{V}`
by putting values
C = `\frac{0.06 C}{9 V}`
C = 0.0067 F
or
C = 6.7 x10⁻³ F -----------------------Ans.
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