A capacitor holds 0.06 coulombs of charge when fully charged by a 9-volt battery. Calculate the capacitance of the capacitor. Ans. (6.67 𝐱10⁻³ F)




Given Data:


Charge on Capacitor = Q 0.06 C 

voltage = 9 V



To Find:


Capacitance C = ? 




Solution:

We know that

Q = CV

or

C = `\frac{Q}{V}`

by putting values

C = `\frac{0.06 C}{9 V}`

C = 0.0067 F

or

C = 6.7 x10⁻³ F -----------------------Ans.

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