A motorboat moves at a steady speed of 4 ms⁻¹. The water resistance acting on it is 4000 N. Calculate the power of its engine. Ans. (16 kW)


Given:  

Speed of the Motorboat = v = 4 m s⁻¹
Water resistance Force on boat = F =  4000 N


To Find:

Power of the boat engine = P = ?  Watt

Solution:   

As Power is defined as the rate of doing work. So,

P = `\frac {W}{t}`

P = `\frac {F ｘS}{t}`

or

P = F ｘ `\frac {S}{t}`   (∴ speed = v = `\frac {S}{t}` )

or

P = F ｘ v   

by putting values 

P = 4000 N ｘ 4 m s⁻¹  

P =  16000 N m s⁻¹  

or

P =  16000 W 

or

P =  16 kW 

Thus the power of the engine is 16 kW

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