A sample of certain radioactive elements has a half-life of 1500 years. If it has an activity of 32000 counts per hour at the present time then plot a graph of the activity of this sample over the period in which it will reduce to 1/16 of its present value.



Data Given:


Half-life of radioactive element = T₁/₂ = 1500 years
Initial count rate = 32000 counts per hour
`\frac{1}{16}`th of the activity = `\frac{32000}{16}` = 2000


To Find:


To Plot a graph


Solution:


Half-life of radioactive element = T₁/₂ = 1500 years
Initial count rate = 32000 counts per hour
Final count rate after 4 half-lives = 2000 counts per hour 
According to the above conditions, we have the below table of data

Count rate per minute

32000

 16000

 8000

 4000

 2000 

 Time (in hours)

0

 1500

 3000

 45000

 60000

Scale : 
Along X-Axis :    One big division = 1500 years
Along y-Axis :    One big division = 8000 counts per hour

The required Graph according to the given data is below
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