Numerical Problem No. 1.7 (Physical Quantities and Measurements) Physics SSC - I (Class 9)

A screw gauge has 50 divisions on its circular scale. The pitch of the screw gauge is 0.5 mm. What is its least count? Ans. (0.001 cm)

Given: 

Numbers of circular scale divisions of Screw gauge = 50

Pitch of the Screw gauge = 0.5 mm

To find: 

Least Count = ?

Solution: 

We know that

 

Least count = `\frac{0.5 mm}{50}`

Least count = 0.01 mm

or

Least count = 0.001 cm

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