Calculate the volume of the following objects:
(i) An iron sphere of mass 5 kg, the density of iron is 8200 kgm⁻³. Ans. (6.1x10⁻⁴ m³)
(ii) 200 g of lead shot having density 11300 kgm⁻³. Ans.(1.77x10⁻⁵ m³)
(iii) A gold bar of mass 0.2 kg. The density of gold is 19300 kgm⁻³. Ans. (1.04x10⁻⁵ m³)
Formula:
As Density is defined as mass per unit volume. So,Density = `\frac {Mass}{Volume}`
or
Volume = `\frac {Mass}{Density}`
(i) An iron sphere of mass 5 kg, the density of iron is 8200 kgm⁻³.
Given:
Mass of an Iron Sphere = 5 kg
Density an Iron Sphere = 8200 kg m⁻³
To Find:
The volume of an Iron Sphere = ?
Solution:
According to the formula
Volume = `\frac {Mass}{Density}`
by putting values
Volume= `\frac {5 kg}{8200 kg m⁻³}`
Volume= 0.000609 m³
or
Volume = 6.1 ｘ10⁻⁴ m³
Thus, the volume of an iron sphere is 6.1 ｘ10⁻⁴ m³
(ii) 200 g of lead shot having a density of 11300 kg m⁻³.
Given:
Mass of lead shot = 200 g = 0.2 Kg
Density of lead shot = 11300 Kgm⁻³
To Find:
The volume of lead shot = ?
Solution:
According to the formula
Volume = `\frac {Mass}{Density}`
by putting values
Volume = `\frac {0.2 Kg}{11300 Kgm⁻³}`
Volume= 0.00001769 m³
or
Volume = 1.77 ｘ10⁻⁵ m³
Thus, the volume of the lead shot is 1.77 ｘ10⁻⁵ m³
(iii) A gold bar of mass 0.2 kg. The density of gold is 19300 kg m⁻³
Given:
Mass of a Gold bar = 0.2 KgDensity of a Gold bar = 𝜌 = 19300 Kgm⁻³
To Find:
The volume of a Gold bar = ?
Mass of a Gold bar = 0.2 Kg
Density of a Gold bar = 𝜌 = 19300 Kgm⁻³
To Find:
The volume of a Gold bar = ?
Solution:
According to the formula
Volume = `\frac {Mass}{Density}`
by putting values
Volume = `\frac {0.2 Kg}{19300 Kgm⁻³}`
Volume = 0.00001036 m³
or
Volume = 1.04 ｘ10⁻⁵ m³
According to the formula
Volume = `\frac {0.2 Kg}{19300 Kgm⁻³}`
Volume = 0.00001036 m³
or
Volume = 1.04 ｘ10⁻⁵ m³
Thus the Volume of a Gold bar is 1.04 ｘ10⁻⁵ m³
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