Numerical Problem No. 3.10 (Dynamics) Physics SSC - I (Class 9)

How much centripetal force is needed to make a body of mass 0.5 kg to move in a circle of radius 50cm with a speed 3 ms⁻¹ ? Ans. (9 N)

Given:  

Mass of the block = m = 0.5 kg

Radius of the circle = r = 50 cm = 0.5 m

Speed of the body = v = 3 m s⁻¹

To Find:

Centripetal Force  = `\F_c` =   ? 

Solution:  

As we know that the formula for static friction is 

`\F_c` = `\frac {mv^2}{r}`

putting values 

`\F_c` = `\frac {0.5 kg (3 m s⁻¹)^2}{0.5 m}`

by simplifying we get

F_c = 9 N

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