How much is the force of friction between a wooden block of mass 5 kg and the horizontal marble floor? The coefficient of friction between wood and the marble is 0.6. Ans. (30 N)


Given:  

Mass of the block = m = 5 Kg
Coefficient of friction = 𝛍 = o.6
Gravitational Acceleration = g = 10 ms⁻²

To Find:
Force of friction = Fs =   ? 

Solution:  

As we know that the formula for static friction is
 
Fs = 𝛍 R    (where R=W=mg) So,

Fs = 𝛍 mg

by putting values 

Fs = 0.6 ｘ 5 Kg ｘ 10 ms⁻²

Fs = 30 N

Thus, the force of friction between a wooden block of mass 5 kg and the horizontal marble floor is 30 N

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