Two blocks of masses 5 kg and 3 kg are suspended by the two strings as shown. Find the tension in each string. Ans.  (80 N, 30 N)

Given:  

Let Mass of  the upper block = m1 = 5 kg
Mass of  the lower block = m2 = 3 kg
using Gravitational Acceleration = g = 10 ms⁻² So,
Weight of  the upper block = W1 = m1 g = 5 kg ｘ 10 m s⁻² = 50 N
Weight of  the lower block = W2 = m2 g = 3 kg ｘ 10 ms⁻² = 30 N

To Find:

Tension in the upper string  = T1 =   ? N
Tension in the lower string  = T2 =   ? N

Solution:  

According to the 1st condition of Equilibrium

Σ F = 0  or (Upwards forces = downwards forces)


Tension in the lower string  = weight of the lower block

T1  = W1 = 30 N

thus, the tension in the lower string is 30 N

Tension in the upper string  = weight of upper block + weight of the lower block

T2  = W2 + W2 = 50 N + 30 N =  80 N

Thus, the tension in the lower string is 80 N

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