Numerical Problem No. 4.8 (Turning Effect of Forces) Physics SSC

Two blocks of masses 5 kg and 3 kg are suspended by the two strings as shown. Find the tension in each string. Ans. (80 N, 30 N)

Given:

Let Mass of the upper block =

m_{1}

$\m_1$ = 5 kg

Mass of the lower block =

m_{2}

$\m_2$ = 3 kg

using Gravitational Acceleration = g = 10 ms⁻² So,

Weight of the upper block = _{$W_{1}$ $\W_1$}=

m_{1}

$\m_1$ g = 5 kg ｘ 10 m s⁻² = 50 N

Weight of the lower block _{= _{$W_{2}$ $\W_2$}}=

m_{2}

$\m_2$ g = 3 kg ｘ 10 ms⁻² = 30 N

To Find:

Tension in the upper string =

T_{1}

$\T_1$ = ? N

Tension in the lower string =

T_{2}

$\T_2$ = ? N

Solution:

According to the 1st condition of Equilibrium

Σ F = 0 or (Upwards forces = downwards forces)

Tension in the lower string = weight of the lower block

T_{1}

$\T_1$ = _{$W_{1}$ $\W_1$}= 30 N

thus, the tension in the lower string is 30 N

Tension in the upper string = weight of upper block + weight of the lower block

T_{2}

$\T_2$ = _{$W_{2}$ $\W_2$}+

W_{2}

$\W_2$ = 50 N + 30 N = 80 N

Thus, the tension in the lower string is 80 N

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