Two blocks of masses 5 kg and 3 kg are suspended by the two strings as shown. Find the tension in each string. Ans.  (80 N, 30 N)

Given:  

Let Mass of  the upper block = `\m_1` = 5 kg
Mass of  the lower block = `\m_2` = 3 kg
using Gravitational Acceleration = g = 10 ms⁻² So,
Weight of  the upper block = `\W_1` = `\m_1` g = 5 kg ｘ 10 m s⁻² = 50 N
Weight of  the lower block = `\W_2` = `\m_2` g = 3 kg ｘ 10 ms⁻² = 30 N

To Find:

Tension in the upper string  = `\T_1` =   ? N
Tension in the lower string  = `\T_2` =   ? N

Solution:  

According to the 1st condition of Equilibrium

Σ F = 0  or (Upwards forces = downwards forces)


Tension in the lower string  = weight of the lower block

`\T_1`  = `\W_1` = 30 N

thus, the tension in the lower string is 30 N

Tension in the upper string  = weight of upper block + weight of the lower block

`\T_2`  = `\W_2` + `\W_2` = 50 N + 30 N =  80 N

Thus, the tension in the lower string is 80 N

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