Calculate an increase in the length of an Aluminum bar 2 m long when heated from 0°C to 20°C. The thermal coefficient of linear expansion of Aluminum is 2.5 x10⁻⁵K⁻¹. Ans. (0.1cm)
Given:
Original (Initial) Length of an Aluminum bar = Lₒ = 2 mInitial Temperature = T₁ = 0°C = (0 + 273) K = 273 K
Final Temperature = T₂ = 20°C = (20 + 273) K = 293 K
Thermal Coefficient of Linear expansion of Aluminum = 𝝰 = 2.5 x10⁻⁵K⁻¹
To Find:
Increase in Length = L - Lₒ = ?
Solution:
L - Lₒ = 𝝰 Lₒ ( T₂ - T₁)
by putting values
L - Lₒ = 2.5 x10⁻⁵K⁻¹ x 2 m (293 K - 273 K)
L - Lₒ = 2.5 x10⁻⁵K⁻¹ x 2 (20 K)
L - Lₒ = 2.5 x10⁻⁵K⁻¹ x 40 mK
L - Lₒ = 100 x10⁻⁵ m
L - Lₒ = 1 x10⁻³ m
L - Lₒ = 0.001 m
or
L - Lₒ = 0.1 cm
Thus the increase in length of Aluminum after heating is 0.1 cm
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