Calculate an increase in the length of an Aluminum bar 2 m long when heated from 0°C to 20°C. The thermal coefficient of linear expansion of Aluminum is 2.5 x10⁻⁵K⁻¹. Ans. (0.1cm)


Given:

Original (Initial) Length of an Aluminum bar = Lₒ = 2 m
Initial Temperature = T₁0°C = (0 + 273) K = 273 K
Final Temperature T₂ = 20°C = (20 + 273) K = 293 K
Thermal Coefficient of Linear expansion of Aluminum = 𝝰 = 2.5 x10⁻⁵K⁻¹

To Find:

Increase in Length = L - Lₒ  = ?

Solution:  

The formula for an increase in length is 

L - Lₒ  = 𝝰 Lₒ ( T₂  - T₁)

by putting values 

L - Lₒ  = 2.5 x10⁻⁵K⁻¹ x 2 m (293 K - 273 K)

L - Lₒ  = 2.5 x10⁻⁵K⁻¹ x 2 (20 K)

L - Lₒ  = 2.5 x10⁻⁵K⁻¹ x 40 mK 

L - Lₒ  = 100 x10⁻⁵ m 

L - Lₒ  = 1 x10⁻³ m 

L - Lₒ  = 0.001 m 

or

L - Lₒ  = 0.1 cm 

Thus the increase in length of Aluminum after heating is 0.1 cm

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