How much heat is required to increase the temperature of 0.5kg of water from 10°C to 65°C? Ans.  (115500 J)


Given:

Mass of water  = m = 0.6 Kg
Initial Temperature = T₁ = 10°C = (10 + 273) K = 283 K
Final Temperature = T₂ = 65°C = (65 + 273) K = 338 K
Change in Temperature = ΔT = T₂  - T₁ = 338 K - 283 K = 55 K
Specific heat of water  = c ≈ 4200 J Kg⁻¹ K⁻¹

To Find:

Heat  = Q  = ?

Solution:  

The formula for heat capacity is 

Q  = mcΔT

By Putting values

Q  = 0.6 Kg ｘ 4200 JKg⁻¹K⁻¹ ｘ 55 K

Q  = 115,500 J

Thus the heat required is 115,500 J

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