If a vector â†’B→B is added to vector  â†’A→A, the result is 6ˆiˆi + ˆjˆj . If  â†’B→B is subtracted from  â†’A→A, the result is -4 Ë†iˆi + 7ˆjˆj . What is the magnitude of vector â†’A→A?⃗⃖

(Ans: 4.1)


Given:

→A + â†’B = 6ˆi + ˆj 
→A - â†’B = -4ˆi + 7ˆj


To Find:

Magnitude of the Vector = |→A| = ?


Solution: 

By adding the given two equations we get

→A + â†’B = 6ˆi + ˆj 
→A - â†’B = -4ˆi + 7ˆj
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2→A     = 2ˆi + 8ˆj

or (dividing both sides by 2)

→A  = ˆi + 4ˆj

Here x-component = 1 and y-component = 4 . So, to find its magnitude |→A| we have

|→A| = âˆšx2+y2

by putting values 

A = âˆš(1)2+(4)2

A = âˆš1+16

A = âˆš17

A = 4.1    --------Ans

Thus the magnitude of the vector â†’A is 4.1


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Numerical Problem 2.5
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List of 11th Physics Numerical Problems of Chapter - 2
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