If a vector `\vec {B}` is added to vector `\vec {A}`, the result is 6`\hat {i}` + `\hat {j}` . If `\vec {B}` is subtracted from `\vec {A}`, the result is -4 `\hat {i}` + 7`\hat {j}` . What is the magnitude of vector `\vec {A}`?⃗⃖
(Ans: 4.1)
Given:
`\vec {A}` + `\vec {B}` = 6`\hat {i}` + `\hat {j}``\vec {A}` - `\vec {B}` = -4`\hat {i}` + 7`\hat {j}`
To Find:
Magnitude of the Vector = |`\vec {A}`| = ?Solution:
By adding the given two equations we get
`\vec {A}` + `\vec {B}` = 6`\hat {i}` + `\hat {j}`
`\vec {A}` - `\vec {B}` = -4`\hat {i}` + 7`\hat {j}`
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2`\vec {A}` = 2`\hat {i}` + 8`\hat {j}`
or (dividing both sides by 2)
`\vec {A}` = `\hat {i}` + 4`\hat {j}`
Here x-component = 1 and y-component = 4 . So, to find its magnitude |`\vec {A}`| we have
|`\vec {A}`| = `\sqrt {x^2 + y^2}`
by putting values
A = `\sqrt {(1)^2 + (4)^2}`
A = `\sqrt {1 + 16}`
A = `\sqrt {17}`
A = 4.1 --------Ans
Thus the magnitude of the vector `\vec {A}` is 4.1
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Numerical Problem 2.5 ⇑ |
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