Numerical Problem No. 2.3 (Vectors and Equilibrium) Physics HSSC - I (Class -11) (Punjab Curriculum and Text Board, Lahore) With Verified Answers

What is the unit vector in the direction of the vector A=4 i +3 j ?

Given:

`\vec {A}` = 4 `\hat {i}` + 3 `\hat {j}`

To Find:

Unit Vector = `\hat {A}` = ?

Solution: 

By definition: A vector dived by its magnitude is called a unit vector. Mathematically it is written as

`\hat {A}` = `\ frac {vec {A}}{vec {A}}`  ----eqn (1)

as given `\vec {A}` = 4 `\hat {i}` + 3 `\hat {j}` Here x-component = 4 and y-component = 3. So, to find its magnitude |`\vec {A}`| we have

|`\vec {A}`| = `\sqrt {x^2 + y^2}`

by putting values 

A = `\sqrt {4^2 + 3^2}`

A = `\sqrt {16 + 9}`

A = `\sqrt {25}`

A = 5

so eqn (1) 

`\hat {A}` = `\ frac {4 \hat {i} + 3 \hat {j} }{5}`  ----- Ans

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Numerical Problem 2.3
⇑

List of 11th Physics Numerical Problems of Chapter - 2

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Numerical Problem 2.2  ⇚   11th Physics Main Content List    ⇛ Numerical Problem 2.4

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