A football leaves the foot of a punter at an angle of 54° positive direction at a speed of 21 m/s. Determine the horizontal and vertical components of the velocity. (Ans. 12m/s and 17m/s)

Given:

Speed of the ball = V = 21 m/s
Angle θ with positive direction (X-axis) = 54° 

To Find:

The horizontal component of velocity = vx = ?
The horizontal component of velocity = vy = ?

Solution:

We know that 
The horizontal component of velocity = vx = v cos θ
So, putting vales

vx = 21 m/s cos 54° = 21 m/s x 0.588 = 12.34 m/s 

vx = 12 m/s -------------Ans 1

Similarly, the Vertical component of velocity = vy = v sin θ
So, putting vales

vy = 21 m/s sin 54° = 21 m/s x 0.809 = 16.99 m/s 

vy = 17 m/s  --------------Ans 2


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