If 280 J of work is done in carrying a charge of 2 C from a place where the potential is -12 V to another place where the potential is V, calculate the value of V. (Answer 128 V)  



Given:

Work done = W = 280 J  

Charge = q = 2 C

Let given Potential = V' = -12 V

To Find:

Potential at another place = V = ?


Solution:


We know that ΔV   = `\frac {W}{q}`

where ΔV = V - V'

So,

V - V' = `\frac {W}{q}`

or

V  = `\frac {W}{q}` + V'

putting values

V  = `\frac {280 J}{2 C}` + (-12 V)

V  = `\frac {280 J}{2 C}` + (-12 V)

V  = 140 J/C -12 V

V  = 128 V ----------------Ans.



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