Calculate the resistance of wire 10 m long that has a diameter of 2 mm and resistivity of 2.63 x 10⁻² Ω m. Answer (83715.3 Ω)
Given:
Length of wire = L = 10 m
Diameter of wire = D = 2 mm = 2 x 10⁻³ m
Radius of wire = r = `\frac {D}{2}` = `\frac {2 x 10⁻³ m} = 1 x 10⁻³ m
Resistivity of the wire = የ = 2.63 x 10⁻² Ωm
To Find:
Resistance of wire = R = ?
Solution:
The formula for finding the Resistance R according to the given data is
R = የ `\frac {L}{A}` ----------(1)
where cross sectional area = A = ã„« r² = (3.1416)( 1 x 10⁻³ m)² = 3.1416 x 10⁻⁶ m²
Now putting values in equation (1)
R = 2.63 x 10⁻² Ωm x `\frac {10 m}{3.1416 x 10⁻⁶ m² }`
R = 2.63 x 10⁻² Ωm x 3.183 x 10⁶ m⁻¹
R = 8.37153 x 10⁻²⁺⁶ Ω
R = 8.37153 x 10⁴ Ω
or
R = 83715.3 Ω ------------Ans.
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© 2022-Onwards by Academic Skills and Knowledge (ASK)
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