Solved Numerical Problem No.6 ( Unit-12: Current Electricity ); HSSC-II (Class-12); Physics (New Book/KPK Text Board, Peshawar) With Verified Answers

A 10-watt resister has a value of 120 Ω. What is the rated current through the resister? Answer (0.2886 A) 

Given:

Power of resister =  P = 10 w

Resistance of resister  = R = 120 Ω

Time = t = 5 min = 300 s

To Find:

Current through the resister = I = ?

Solution:

We know that 

P = I² R

or 

I² = `\frac {P}{R}`

or 

I = `\sqrt frac {P}{R}`

by putting values

I = `\sqrt frac {10 w}{120 Ω}`

I = `\sqrt frac {10 W}{120 Ω}`   [ ∴ w = A²Ω]

I = `\sqrt {0.0833 A²}`

I = 0.2886 A  -------------------Ans.

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