A resistor of 50 Ω has a P. D. of 100 V, D.C. across 1 hour. Calculate (a). Power and (b). Energy. Answer ( (a) 200W, (b) 0.72 MJ ) 



Given:

Resistance of resister  = R = 50 Ω

Potential Difference =  V = 100 V

Time duration = Δt = 1 hour = 60 ｘ 60 s =3600 s

To Find:

Power = P = ?

Energy = E = ?

Solution:


The formula for power according to given quantities is

P = `\frac {V^2}{R}`

by putting values

P = `\frac {(100 V)^2}{50 Ω}`

P = `\frac {(10,000 V^2}{50 Ω}` 

P = 200 W ---------------Ans. (1)

---------------------------------------


To find E we know that

E = P ｘ t

putting values

E = 200 w ｘ3600 s

E = 720,000 J

or

E = 7.2 ｘ 10⁻⁵ J

or

E = 0.72 ｘ 10⁻⁶ J

or

E = 0.72 MJ  -------------------Ans. (2)




************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.