Calculate the current through a single loop circuit if Ɛ = 120 V, R = 1000 Ω, and internal resistance r = 0.01 Ω. Answer (120 mA) 



Given:

Battery e.m.f =  Ɛ =  120 V

Resistance of the circuit = R = 1000 Ω

Internal resistance of the e.m.f source= r = 0.010 Ω

To Find:

Current through the single loop = I = ?


Solution:

Since we have

Ɛ = I ( R + r )

or

I = `\frac {Ɛ}{R + r}`

by putting the corresponding values

I = `\frac {120 V}{1000 Ω + 0.010 Ω}`

I = `\frac {120 V}{1000.010 Ω}`

I = 0.1199988 A

I = 0.120 A

I = 120 ｘ 10⁻³ A

I = 120 mA ------------------ Ans.



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