How a 5 mA, 100 Ω galvanometer is converted into a 20 V voltmeter? (Answer: RHRH = 1900 N) 



Given:

Current through the galvanometer = IgIg = 5 mA = 5 ｘ 10⁻³ A

Resistance  = RgRg = 100 Ω

Total Voltage = V = 20 V


To Find:

High Resistance = RhRh = ?


Solution:

The formula for shunt Resistant RhRh is


RhRh = VIgVIg- IgIg

by putting the corresponding values


RhRh = 20V5ｘ10⁻³A- 100 A

Rh = 4000 Ω - 100 Ω

Rh = 3900 Ω ---------------------Ans. 




************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.