An inductor with an inductance of 100 µH passes a current of 10 mA when its terminal voltage is 6.3 V. Calculate the frequency of A.C supply. Ans (10⁶ Hz) 



Data Given:

Inductance = L = 100 μH = 100 × 10⁻⁶ H

Current = I = 10 mA = 10 × 10⁻³ A

Voltage = V = 6.3 V



To Find:

Frequency of A.C. supply = f = ?


Solution:

The formula for the Frequency of A.C. supply is given by 

f = `\frac {X_L}{2ㄫL}`

Where `\X_L` = Inductive Reactance =  `\frac {V}{I}` so,

f = `\frac {V}{2ㄫ L I}`

Now putting the corresponding values 

f = `\frac {6.3 V}{2 × 3.1416 × 100 × 10⁻⁶ H × 10 × 10⁻³ A}`

f = `\frac {6.3 V}{6283.185 × 10⁻⁹ H A}`

f = 0.00100 × 10⁹ Hz

or

f = 1.0 × 10⁶ Hz -------------Ans.



************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.