(a) Calculate the inductive reactance of a 3.00 mH inductor, when 60.0 Hz and 10.0 kHz AC voltages are applied. (b) What is the RMS current at each frequency if the applied RMS voltage is 120 V? Ans ((a) 1.13 Ω, 188 Ω (b) 106 A, 0.637 A)
Data Given:
Inductance of an inductor = L = 3.00 mH = 3.00 × 10⁻³ H
1st value of Frequency = f₁ = 60 Hz
2nd value of Frequency = f₂ = 10 k Hz = 10 × 10³ Hz
Voltage (rms) = VrmsVrms = 120 V
To Find:
(a)
Inductive reactance at f₁ = XL₁XL₁ = ?
Inductive reactance at f₂ = XL₂XL₂ = ?
(b)
Root Mean Square current at f₁ = Irms₁Irms₁ = ?
Inductive reactance at f₂ = Irms₂Irms₂ = ?
Solution:
(a)
The general formula for Inductive Reactance is
XLXL = 2ㄫ f L
At Frequency f₁
XL₁XL₁ = 2ㄫ f₁ L
putting values
XL₁XL₁ = 2 × 3.1416 × 60 Hz × 3.00 × 10⁻³ H
XL₁XL₁ = 1.13 Ω --------------Ans. (1)
And at Frequency f₂
XL₂XL₂ = 2ㄫ f₂ L
putting values
XL₂XL₂ = 2 × 3.1416 × 10 × 10³ Hz × 3.00 × 10⁻³ H
XL₂XL₂ = 188.4 Ω -----------------Ans. (2)
(b)
The general formula for Root Mean Square current is
IrmsIrms = VrmsXLVrmsXL
So, at frequency f₁
Irms₁Irms₁ = VrmsXL₁VrmsXL₁
putting values
Irms₁Irms₁ = 120V1.13Ω120V1.13Ω
Irms₁Irms₁ = 106.195 A -------------Ans.(3)
And at Frequency f₂
Irms₂Irms₂ = VrmsXL₂VrmsXL₂
putting values
Irms₂Irms₂ = 120V188.4Ω120V188.4Ω
Irms₂Irms₂ = 0.637 A -------------Ans.(4)
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