A transistor is connected in the CE configuration. The voltage drop across the load resistance (Rc) 3 k Ω is 6 V. Find the base current. The current gain of the transistor is 0.97. Answer (2.06 ｘ10⁻³ A) 



Given:

Load resistance = RC = 3 kΩ = 3ｘ10³ Ω

Voltage drop at load = VC =  6 V

Current gain = β =  0.97


To Find:

Base Current = IB =  ?



Solution:


Using the Current gain β formula


β = ICIB 

or 

IB = ICβ -----------(1)

where IC is unknown and can be calculated by Using Ohm's Law

 IC  = VCR

putting values

IC  = 6V3ｘ10³Ω

IC  = 2ｘ10⁻³ A 


Now putting the corresponding values in equation (1)

IB = 2ｘ10⁻³A0.97

IB = 2.06ｘ10³ A 

or

IB = 2.06 mA -------------Ans.





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