A string 1m long is used to whirl a 100g stone in a horizontal circle at a speed of 2m s⁻¹. Find the tension in the string. ( T = 0.4 N)


Given:

Length of the string = Radius of the horizontal circle = r = 1 m 
Mass of  stone = m = 100 g = 0.1 kg
Velovity of  stone = m = 2 m s⁻¹

To Find:

Tension in string = T = ?

Solution:

The tension in the string will be the same as the magnitude of the centripetal force. So,

T = Fc =`\frac {mv²}{r}`

putting values

T  =`\frac {0.1 kg ｘ ( 2 m s⁻¹)²}{1 m}`

T  =`\frac {0.1 kg ｘ 4 m² s⁻²}{1 m}`

T  = 0.4 kg m s⁻²

or

T  = 0.4 N ----------------Ans.

Thus, the tension in the string is 0.4 N



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