Compare the theoretical speeds of sound in hydrogen (MHMH = 2.0 g/mol, ƔH =1.4) with helium (MHe = 4.0 g mol⁻¹, ƔHe = 1.66 & R = 8334 j k⁻¹ mol⁻¹) at 0°C .( vHe = 0.77 vH)
Given:
MH = 2.0 g/mol
ƔH =1.4
MHe = 4.0 g mol⁻¹
ƔHe = 1.66
R = 8334 j k⁻¹ mol⁻¹
T = 0°C = 273 K
To Find:
Comparison of the theoretical speeds of sound in hydrogen with helium = vHevH = ?
Solution:
To find the speed v of sound in a gas is given by:
v = √ƔRTM
Speed `\v_{He} of sound in Helium (He) gas
vHe = √ƔHexRxTM
vHe = √1.66x8334jk⁻¹mol⁻¹x273K4kg
vHe = √944,200.53m²s⁻²
vHe = 972 m s⁻¹
Speed vH of sound in Hydrogen (H) gas
vH = √ƔHxRxTM
vH = √1.4x8334jk⁻¹mol⁻¹x273K2kg
vH = √1,592627.4m²s⁻²
vH = 1262 m s⁻¹
Now
vHevH = 972ms⁻¹1262ms⁻¹
vHevH = 0.77
or
vHe = 0.77 vH
************************************
Shortcut Links For
1. Website for School and College Level Physics 2. Website for School and College Level Mathematics 3. Website for Single National Curriculum Pakistan - All Subjects Notes
© 2022-Onwards by Academic Skills and Knowledge (ASK)
Note: Write me in the comment box below for any query and also Share this information with your class-fellows and friends.
1. Website for School and College Level Physics
2. Website for School and College Level Mathematics
3. Website for Single National Curriculum Pakistan - All Subjects Notes
© 2022-Onwards by Academic Skills and Knowledge (ASK)
Note: Write me in the comment box below for any query and also Share this information with your class-fellows and friends.
0 Comments
If you have any QUESTIONs or DOUBTS, Please! let me know in the comments box or by WhatsApp 03339719149