It is desired to make an A.C generator that can produce an emf of 5 kV with 50 Hz frequency. A coil of area 1 m² consisting of 200 turns is used as an armature. What should be the magnitude of the magnetic field in which the coil rotates? (Ans: 0.08 T). 



Data Given:

Maximum value emf produced= `\Ɛ_0` = 5 kV = 5 ｘ10³ V

Frequency = f = 50 Hz

Area of coil = A = 1 m²

Number of turns = N = 200 



To Find:


Magnetic field strength = B = ?


Solution:

The relation for the Maximum value of emf  `\Ɛ_0` is given 

`\Ɛ_0`  = B ധ N A

where ധ = 2πf

or

B = `\frac {Ɛ_0}{2πfNA}`


Putting the corresponding values 


B = `\frac {5 ｘ10³ V}{2 ｘ 3.1416 ｘ 50 Hz ｘ 200 ｘ 1 m²}`


B = `\frac {5000 V}{62832 Hz m²}`

B = 0.0796 T

or

B = 0.08 T -------------Ans.





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