Two coils are placed side by side. An emf of 0.8 V is observed in one coil when the current is changing at the rate of 200 A s⁻¹ in the other coil. What is the mutual inductance of the coils? (Answer: 4 mH). 



Data Given:

emf in secondary coil = `\Ɛ_S` = 0.8 V

Current changing rate in primary coil  = `\frac {△I_p}{△t}` = 200 A s⁻¹



To Find:


Mutual Induction = M = ?


Solution:


Using the following relation

`\Ɛ_S` =  M `\frac {△I_p}{Δt}`

or

M = `\frac {Ɛ_S}{{△I_p}/{Δt}}`

by putting the corresponding values

M = `\frac {0.8 V}{200 A s⁻¹}`

M = 0.004 H

or

M = 4 ｘ 10⁻³ H

or

M = 4 mH ----------------Ans.




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