Two coils are placed side by side. An emf of 0.8 V is observed in one coil when the current is changing at the rate of 200 A s⁻¹ in the other coil. What is the mutual inductance of the coils? (Answer: 4 mH). 



Data Given:

emf in secondary coil = ƐS = 0.8 V

Current changing rate in primary coil  = △Ip△t = 200 A s⁻¹



To Find:


Mutual Induction = M = ?


Solution:


Using the following relation

ƐS =  M △IpΔt

or

M = ƐS△IpΔt

by putting the corresponding values

M = 0.8V200As⁻¹

M = 0.004 H

or

M = 4 ｘ 10⁻³ H

or

M = 4 mH ----------------Ans.




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