A pair of adjacent coils has a mutual inductance of 0.75 H. If the current in the primary changes from 0 to 10 A in 0.25 s, what is the average induced emf in the secondary? What is the change in flux in it if the secondary has 500 turns? (Answer: 300 V, 1.5 𝐱 10⁻¹ Wb).
Data Given:
Mutual Induction = M = 0.75 H
Current change in primary coil = △Ip△Ip = 10 A - 0 A = 10 A
Time interval = △t = 0.25 s
Number of turns in secondary coil = Nₛ = 500 turns
To Find:
Induced emf in secondary coil = ƐS = ?
Change in flux = Δф = ?
Solution:
Using the following relation
ƐS = M △IpΔt --------(1)
by putting the corresponding values
ƐS = 0.75 H x10A0.25s
ƐS = 30 V ---------------Ans.1
We have another relation for induced emf in the secondary coil.
ƐS = Nₛ ΔфΔt -------------(2)
by comparing equations (1) and (2)
Nₛ ΔфΔt = M △IpΔt
or
Δф = MNₛ x ΔI_p
by putting values
Δф = 0.75H500 x 10 A
Δф = 0.15 Web
or
Δф = 1.5 x 10⁻¹ Web ------------Ans.2
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