Find the value of the current flowing through a capacitance of 0.5 μF when connected to a source of 150 V at 50 Hz. (Ans: `\I_{rms}` = 0.024 A )



Data Given:

Voltage (rms) = `\V_{rms}` = 150 V

Capacitance = C = 0.5 μF = 0.5 × 10⁻⁶ F

Frequency = f = 50 Hz




To Find:

Root Mean Square current = `\I_{rms}` = ?



 

Solution:


The general formula for Root Mean Square current is 

`\I_{rms}` = `\frac {V_{rms}}{X_C}`

Where `\X_C` =`\frac {1}{ധC}` = `\frac {1}{2πfC}`

`\I_{rms}` = `\frac {V_{rms}}{1/{2πfC}}`

or

`\I_{rms}` = `\V_{rms}` (2πfC)

putting values

`\I_{rms}` = 150 V (2 × 3.1416 ×  50 Hz × 0.5 × 10⁻⁶ F)

`\I_{rms}` = 150 V (157.08 × 10⁻⁶ F Hz)

`\I_{rms}` = 23562 × 10⁻⁶ A

`\I_{rms}` = 0.023562 A

`\I_{rms₁}` = 0.024 A -------------Ans.



************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.