What is the resonant frequency of a circuit which includes a coil of inductance 2.5 H and a capacitance of 40 μF? (Ans: 15.9 Hz ) 



Data Given:


Inductance = L = 2.5 H

Capacitance of capacitor = C = 40 μF = 40 x10⁻⁶ F



To Find:


Resonant Frequency  = fr = ?


Solution:


The formula for resonant frequency is

fr = 12LC

By putting values

fr = 123.14152.5H4010F

fr = 16.28310010s²

fr = 16.28310s²

fr = 16.28310²s

fr = 0.159  10² s⁻¹

or


fr = 15.9 Hz -----------------Ans.




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