A 1.0 m long copper wire is subjected to stretching force and its length increases by 20 cm. Calculate the tensile strain and the percent elongation which the wire undergoes. (Ans: 0.2, 20 % )



Given Data:

Length of the Copper wire = L =  1 m 

Increased Length = ΔL=  20 cm = 0.2 m


To Find:

Tensile Strain = Ɛ = ?



Solution:


The formula for tensile strain Ɛ is

Ɛ = `\frac {ΔL}{L}`

putting values

Ɛ = `\frac {0.2 m}{1 m}`

Ɛ = 0.2 ----------Ans.1


Now the formula for % elongation is

% elongation =  `\frac {ΔL}{L}` ｘ 1oo %

% elongation =  Ɛ ｘ 1oo %

% elongation =  0.2 ｘ 1oo %

% elongation =  20 % ------------Ans.2




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