The current flowing into the base of a transistor is 100 μA. Find its collector current Ic, its emitter current Iɛ, and the ratio ICIEICIE. If the value of the current gain β is 100. Answer (10 mA, 10.1mA, 0.99) 




Given:

Base Current = IBIB  = 100 μA = 100 ｘ10⁻⁶ A

Current gain = β = 100



To Find:

1. Collector Current = ICIC = ?

2. Emitter Current = IEIE = ?

3. Ratio ICIEICIE = ?



Solution:


1. Collector Current = ICIC = ?


Using the Current gain β formula 


β = ICIBICIB 

or

ICIC = β ｘ IBIB

putting values

ICIC = 100 ｘ 100 ｘ10⁻⁶ A

ICIC = 1 ｘ10⁻² A

or

ICIC = 10 ｘ10⁻³  A

ICIC = 10 mA --------------Ans. (1)



2. Emitter Current = IEIE = ?

Since the Emitter Current IEIE is the sum of the Base current IBIB  and collector current ICIC ie.

IEIE =  IBIB  + ICIC
 
by putting values

IEIE =  100 ｘ10⁻⁶ A + 10 ｘ10⁻³  A

IEIE =  0.1 ｘ10⁻³ A + 10 ｘ10⁻³  A

IEIE =  10.1 ｘ10⁻³  A 

IEIE =  10.1 mA ------------Ans. (2)



3. Ratio ICIEICIE = ?

The required Ratio is 

ICIEICIE = 10ｘ10⁻³A10.1ｘ10⁻³A

ICIE = 0.990 ---------------Ans. (3)



************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.