Fig.P.18.2 shows a transistor that operates a relay as the switch S is closed. The relay is energized by a current of 10 mA. Calculate the value R, which will just make the relay operate. The current gain β of the transistor is 200. When the transistor conducts, its VBC can be assumed to be 0.6 V. (Ans: 168 kΩ)
Given:
Collector Current = IC = 10 mA = 10 x10⁻³ A
Current gain = β = 200
Voltage at Base Current = VBC = 0.6 V
Voltage at Collector Current = VCC = 9 V (given in the Figure)
To Find:
Resistance at Base = RB = ?
Solution:
We know that
VCC = IB RB + VBC
or
RB = VCC-VBCIB -----------(1)
where IB is unknown and can be calculated from the gain formula
β = ICIB
or
putting values
IB = 0.05x10⁻³ A
Now putting the corresponding values in equation (1)
RB = 9V-0.6V0.05x10⁻³A
RB = 8.4V0.05x10⁻³A
RB = 168x10³ Ω
or
RB = 168 KΩ -------------Ans.
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