Fig.P.18.2 shows a transistor that operates a relay as the switch S is closed. The relay is energized by a current of 10 mA. Calculate the value R, which will just make the relay operate. The current gain β of the transistor is 200. When the transistor conducts, its VBC can be assumed to be 0.6 V. (Ans: 168 kΩ)

Given:

Collector Current = IC =  10 mA = 10 x10⁻³ A

Current gain = β = 200

Voltage at Base Current = VBC =  0.6 V

Voltage at Collector Current = VCC =  9 V (given in the Figure)


To Find:

Resistance at Base = RB  ?



Solution:


We know that

VCCIB RB  +  VBC

or 

RB VCC-VBCIB -----------(1)

where IB is unknown and can be calculated from the gain formula

β = ICIB

or

IB = ICβ

putting values

IB = 1010³A200

IB  = 0.05x10⁻³ A 


Now putting the corresponding values in equation (1)

RB 9V-0.6V0.0510³A

RB = 8.4V0.0510³A

RB 168x10³ Ω 

or

RB 168  -------------Ans.



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