Solved Numerical Problem No. 18.5 ( Unit-18: Electronics); HSSC-II (Class-12); Physics (Punjab Curriculum and Text Board, Lahore) With Verified Answers

Calculate the gain of the non-inverting amplifier shown in Fig.P.18.5.  Answer ( 5 )

Given:

Resistance 1 = `\R_1` = 10 kΩ = 10ｘ10³ Ω

Resistance 2 = `\R_2` = 40 kΩ = 40ｘ10³ Ω

To Find:

Gain = `\G` =  ?

Solution:

The formula for Gain "`\G`" is

`\G` =  1 + `\frac {R_2}{R_1}`

By putting values

`\G` =  1 + `\frac {40ｘ10³ Ω}{10ｘ10³ Ω}`

`\G` =  1 + 4

`\G` =  5 -----------------Ans

************************************

Shortcut Links For 

1. National MDCAT, ECAT, JOB EXAM Physics MCQs Preparation (New) 
2. Physics (New) 11th Class SLO Based Notes
3. Physics (New) 11th class MCQs Quizzes All Units
4. Physics (New) 12th Class SLO Based Notes
5. Physics (New) 12th class MCQs Quizzes All Units

1. Website for School and College Level Physics   

(https://askrarequiz.blogspot.com)

2. Website for School and College Level Mathematics  

(https://askraremaths.blogspot.com)

3. Website for Single National Curriculum Pakistan - All Subjects Notes 

(https://askrareclassnotes.blogspot.com/)

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.