What are the energies in eV of quanta of wavelength? λ = 400, 500 and 700 nm? (Ans: 3.10 eV. 2.49 eV. 1.77 eV)



Data Given:

Let 

(1) λa = 400 nm = 400 x 10⁻⁹ m 

(2) λb = 500 nm = 500 x 10⁻⁹ m 

(3) λc = 700 nm = 700 x 10⁻⁹ m 


∴ Plank's Constant = h =  6.62 x 10⁻³⁴ m² kg s⁻¹

∴ Speed of light = 3 x 10 m s⁻¹


To Find:


(1) Ea  ? (in eV)   

(2) Eb  ? (in eV) 

(3) Ec  ? (in eV) 


Solution:


The general formula for finding energy for a given wavelength λ is

E = hcλ 

where c is speed of light = 3 x 10 m s⁻¹


(1) Ea  ? (in eV)  

Ea hcλa

by putting values

Ea 6.6210³m²kgs¹310ms¹c40010m 

Ea 19.8610²m³kgs²40010m

Ea 0.04965x 10⁻¹⁷ J

Ea 4.965x 10⁻¹⁹ J

Expressing in eV we have

Ea 4.96510¹1.610¹ eV

Ea = 3.103  eV --------------Ans.1




(2) Eb  ? (in eV)  

Eb = hcλb 

by putting values

Eb 6.6210³m²kgs¹310ms¹c50010m

Eb 19.8610²m³kgs²50010m

Eb 0.03972x 10⁻¹⁷ J

Eb 3.972 10⁻¹⁹ J

Expressing in eV we have

Eb 3.97210¹10¹1.610¹ eV

Eb = 3.483  eV --------------Ans.2





(3) Ec  ? (in eV)  

Ec hcλb

by putting values

Ec = 6.6210³m²kgs¹310ms¹c50010m

Ec 19.8610²m³kgs²70010m

Ec 0.02837x 10⁻¹⁷ J

Ec 2.837 x 10⁻¹⁹ J

Expressing in eV we have

Ec = `\frac {2.837 x 10⁻¹⁹x 10⁻¹⁹ }{1.6 x 10⁻¹⁹ }` eV

Ec = 1.773  eV --------------Ans.3

 


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