The half-life of radioactive nucleus `\ _{86}^{226}Ra` is 1.6 ｘ10³ years. Determine the decay constant. (Answer: 1.4 ｘ 10⁻¹¹ s⁻¹)



Given Data:


half life of radioactive nucleus `\ _{86}^{226}Ra` = `\T_{1∕2}` = 1.6 ｘ10³ years

by converting into Sec (SI unit) we have 1 year = 3.1536 ｘ10⁷ s  

`\T_{1∕2}` = 1.6 ｘ10³ ｘ 3.1536 ｘ10⁷ s = 5.0475 ｘ 10¹⁰ s




To Find:

The decay constant = λ =?



Solution:


Using the formula for Half-life we have

`\T_{1∕2}` = `\frac {0.693}{λ}`


or

 λ = `\frac {0.693}{T_{1∕2}}`


Putting values

 λ = `\frac {0.693}{5.0475 ｘ 10¹⁰ s}`

 λ = 0.1374 ｘ 10⁻¹⁰ s⁻¹

or

 λ = 1.374 ｘ 10⁻¹¹ s⁻¹ ----------------Ans.


Similar Questions:



************************************

Shortcut Links For 


1. Website for School and College Level Physics   
2. Website for School and College Level Mathematics  
3. Website for Single National Curriculum Pakistan - All Subjects Notes 

© 2022-Onwards by Academic Skills and Knowledge (ASK)     

Note:  Write me in the comment box below for any query and also Share this information with your class-fellows and friends.