Calculate the total energy released if 1 kg of  235U 235U undergoes fission? Taking the disintegration energy per event to be Q = 208 MeV. (Answer: 5.32 ｘ 10⁻²⁶ MeV) 



Given Data:

Mass of  235U 235U  = 1 kg

Q = 208 MeV

Atomic mass of  235U 235U = M = 235 kgK⁻¹mol⁻¹

Avogadro number = NANA = 6.023 ｘ 10²² atom K⁻¹ mol⁻¹



To Find:

The total energy released = E =?



Solution:


The formula for energy released during fission is

E = No. of atoms in a sample x  disintegration energy per event

E = NQ ------------------(1)


We have to find first the No. of atom (N = n NANA) in 1 kg given mass   235U 235U So,


n = no. of mole = given mass (m) / Atomic mass (M)


n = 1kg235kgK⁻¹mol⁻¹ = 4.255 ｘ 10⁻³ K mol


 N = No. of atom in   235U = n NA

 N = 4.255 ｘ 10⁻³ K mol ｘ 6.023 ｘ 10²² atom K⁻¹ mol⁻¹

N = 2.56 ｘ 10²⁴ atoms


Now putting values in equation (1)


E = 2.56 ｘ 10²⁴ atoms ｘ 208 MeV


E = 532.48 ｘ 10²⁴ MeV


E = 5.33 ｘ 10²⁶ MeV -----------------Ans.




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