Find the mass defect and the binding energy for tritium, if the atomic mass of tritium is 3.016049 u (Ans : 0.00857 u. 7.97 M e V )



Given Data:


Mass of Tritium = m = 3.016049 u

Atomic mass of Tritium  = A = 3

Atomic number of helium = Z = 1

Mass of Proton = `\m_p` = 1.007276 u


Mass of Neutron = `\m_n`= 1.008665 u





To Find:

mass defect = Δ m =?

Binding energy = B.E =?


Solution:


The mass defect can be calculated by the following formula

 Î” m = ( Z `\m_p` + (A - Z)`\m_n` ) - m

by putting the corresponding values

 Î” m = ( 1 ｘ 1.007276 u  + (3 - 1) ï½˜ 1.008665 u ) - 3.016049 u


 Î” m = 1.007276 u + 2.01733 u - 3.016049 u


Δ m = 0.008557 u -----------------Ans.1



To Find the Binding energy = B.E =?


We know that  1 amu = 931 MeV so,


Binding Energy = B.E = Mass deficit (in amu) ×  931 MeV


B.E = 0.008557 u ×  931 MeV


B.E = 7.966567 MeV

or

B.E = 7.97 MeV --------------------Ans.2



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