The element `\ _{91}^{234}Pa` is unstable and decays by β-emission with a half-life 6.66 hours, state the nuclear reaction and the daughter nuclei. 

(Ans : `\ _{92}^{234}U` )



Given Data:

Element = `\ _{91}^{234}Pa`

β-emission

`\T_{1∕2}` = 6.66 hours



To Find:


Nuclear Reaction = ?

Daughter Nuclei = ?



Solution:


The general reaction for β-emission is

`\ _{Z}^{A}X`  →  `\ _{Z+1}^{A}X` + `\ _{-1}^{0}β` + Energy

According to given conditions, the reaction will be as follows

`\ _{91}^{234}Pa`   →  `\ _{92}^{234}U` + `\ _{-1}^{0}β` + Energy  ----------------Ans.1


the Daughter Nuclei is 

`\ _{92}^{234}U` -----------------Ans.2



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