A football is thrown upward at an angle of 30 degree with respect to the horizontal. To throw a 40 m pass what must be the initial speed of the ball? 

(Ans: 21 m s⁻¹)



Given:

Range of the projectile (football) = R =  40 m

Angle of projection = θ = 30°


To Find:

Initial Speed of the football = = ?


Solution:


Using the formula of Range of projectile

R = v2igsin 2θ

or

viRgsin2θ


by putting the corresponding values

vi = 
40m9.8ms-2sin2x30°

vi = 392m2s-2sin60°

vi = 392m2s-20.866

vi = 452.66m2s-2

vi = 21.3 m s⁻¹ -----------Ans.


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