A truck weighing 2500 kg and moving with a velocity of 21 m s⁻¹ collides with stationary car weighing 1000 kg. The truck and the car move together after the impact. Calculate their common velocity.  

(Ans: 4.0 ï½˜ 10⁻⁶ T)



Given:

Mass of truck = m₁ = 2500 kg

Initial velocity of electron = v₁ = 21 m s⁻¹

Mass of car = m₂ = 1000 kg

Initial velocity of car = v₂ = 0 m s⁻¹ (at rest)


To Find:

Common velocity after impact = v = ?


Solution:


By using Law of conservation of momentum

Momentum before impact = Momentum after impact

m₁ v₁ + m₂ v₂ = (m₁ + m₂) v 

or

v = `\frac {m₁ v₁ + m₂ v₂}{m₁ + m₂}`

Where v is the common velocity of the truck and car after impact


by putting the corresponding values

v = `\frac {2500 kg x 21 m s⁻¹ + 1000 kg x 0 m s⁻¹}{2500 kg + 1000 kg}`

v = `\frac {52500 kg m s⁻¹ + 0 kg m s⁻¹}{3500 kg}`

v = 15 m s⁻¹ ------------------Ans.



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