A body of moment of inertia I = 0.80 kg m² about a fixed axis, rotates with constant angular velocity of 100 rad s⁻¹. Calculate its angular momentum L and the torque to sustain this motion. (Ans: 80 Js, 0)
Data Given:
Constant angular velocity = ധ = 100 rad s⁻¹
To Find:
Angular Momentum = →L = ?
Troque = →T = ?
Solution:
Using formula for Angular momentum L in terms of angular velocity ധ and Moment of inertia I
→L = Iധ
By putting values
→L = 0.80 kg m² x100 rad s⁻¹
→L = 80 kg m² rad s⁻¹
or { as kg m² rad s⁻¹ = Js}
→L = 80 J s
To find Torque T we have a formula in terms of angular acceleration ∝ and Moment of inertia I
→T = I ∝
Since it is given that he body is moving with constant angular velocity, so angular acceleration will be zero i.e ∝ = 0 rad s⁻², thus
→T = 0.80 kg m² x 0 rad s⁻²
→T = 0 N m
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