A body of moment of inertia I = 0.80 kg m² about a fixed axis, rotates with constant angular velocity of 100 rad s⁻¹. Calculate its angular momentum L and the torque to sustain this motion. (Ans: 80 Js, 0)



Data Given:


Moment of inertia = II = 0.80 kg m²

Constant angular velocity = ധ = 100 rad s⁻¹

To Find:


Angular Momentum  = →L→L = ?

Troque = →T→T = ?


Solution:


Using formula for Angular momentum L in terms of angular velocity  ധ and Moment of inertia II

→L→L = IIധ  

By putting values

→L→L = 0.80 kg m² ｘ100 rad s⁻¹  

→L→L = 80 kg m² rad s⁻¹  

or { as kg m² rad s⁻¹ = Js}

→L→L = 80 J s  

To find Torque T we have a formula in terms of angular acceleration  ∝ and Moment of inertia II

→T→T = II ∝

Since it is given that he body is moving with constant angular velocity, so angular acceleration will be zero i.e ∝ = 0 rad s⁻², thus 
→T→T = II ∝

→T→T = 0.80 kg m² ｘ 0 rad s⁻²

→T→T = 0 N m

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