X-ray beam of wavelength undergoes a first order reflection from a crystal when its angle of incident to a crystal face is 26.5°, and an X-ray beam of wavelength 0.097 nm undergoes a third order reflection when its angle of incidence to that face is 60°. Assuming that the two beams reflect from the same family of planes, calculate (a) the interplanar spacing of the planes and (b) wavelength. (Ans: (a) 0.168 nm, (b) 0.150 nm)
Data Given:
For 1st order reflection:
Angle = θ₁ = 26.5°
Wavelength = λ₁ = ?
n₁ = 1
For 3rd order reflection:
Angle = θ₂ = 60°
Wavelength = λ₂ = 0.097 nm = 0.097 x 10⁻⁹ m
n₂ = 3
To Find:
(a) Crystal Interplanar spacing = d = ?
(b) Wavelength of 1st order reflection = λ₁ = ?
Solution:
(a) Crystal Interplanar spacing = d = ?
Using Braggs Equation (3rd order reflection)
2 d sin θ₂ = m₂ λ₂
or
d = m₂λ₂2sinθ₂
by putting the corresponding values
d = 3x0.097x10⁻⁹m2sin60°
d = 0.291x10⁻⁹m2x0.866
by simplifying
d = 0.168 x 10⁻⁹ m
or
d = 0.168 nm ---------------Ans.(1)
(b) Wavelength of 1st order reflection = λ₁ = ?
Again using the brag's formula (for 1st Order reflection)
2d sin θ₁ = m₁ λ₁
or
λ₁ = 2dsinθ₁m₁
by putting the corresponding values
λ₁ = 2x0.168x10⁻⁹mxsin26.5°1
λ₁ = 0.336 x 10⁻⁹ m x 0.446
λ = 0.149856 x 10⁻⁹ m
or
λ₁ = 0.15 nm -----------------------Ans (2)
Again using the brag's formula (for 1st Order reflection)
2d sin θ₁ = m₁ λ₁
λ₁ = 0.336 x 10⁻⁹ m x 0.446
λ = 0.149856 x 10⁻⁹ m
or
λ₁ = 0.15 nm -----------------------Ans (2)
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