In a double slit experiment the second order maximum occurs at θ = 0.25°. The wavelength is 650 nm. Determine the slit separation. (Ans: 0.3 mm)



Data Given:

Order (2nd Maximum) = m = 2

Wavelength of light = λ = 650 nm = 650 ｘ 10⁻⁹ m = 6.50 ｘ 10⁻⁷ m

Angle θ = 0.25°


To Find:

Separation between the slits = d = ?


Solution:


Formula for `m^{th}` maxima we have

d sin θ = m λ

or

d = `\frac {m λ}{sin θ}`

putting the corresponding values

d = `\frac {2 ｘ 6.50 ｘ 10⁻⁷ m}{sin 0.25°}`

d = `\frac {13 ｘ 10⁻⁷ m}{0.0044}`

d = 2954.545 ｘ 10⁻⁷ m

or

d = 0.295 ｘ 10⁻³ m

or

d = 0.3 mm --------------Ans.




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