Physics Numerical Problems No. 9.4, Unit-98: Physical Optics, HSSC-I (class 11) Physics (Punjab Curriculum Textbook Board, Lahore) With Verified Answers

A monochromatic light of wavelength 588 nm is allowed to fall on the half silvered plate G1, in the Michelson interferometer. If mirror M1 is moved through 0.233 mm, how many fringes will be observed to shift? (Ans: 792)

Data Given:

Wavelength of light = λ = 588 nm = 588 ｘ 10⁻⁹ m

Distance moved = P = 0.233 mm = 2.33 ｘ 10⁻¹ｘ 10⁻³ m = 2.33 ｘ  10⁻⁴ m

To Find:

Number of  fringe = m =  ?

Solution:

The formula for the total distance P is

P = m`\frac {λ}{2}`

or

m = `\frac {2P}{λ}`

by putting values

m = `\frac {2 ｘ 2.33 ｘ 10⁻⁴ m}{588 ｘ 10⁻⁹ m}`

m =  0.00792 ｘ 10⁻⁴⁺⁹

m =  0.00792 ｘ 10⁵

or

m =  792 ｘ 10⁻⁵ ｘ 10⁵

or

m =  792 fringes -------------Ans.

Similar Questions:

When the movable mirror of a Michelson interferometer is moved 0.1 mm. How may dark fringes pass through the reference point, if light of wavelength 580 nm is used? (Ans. 345 fringes)

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