12th Class Physics MCQs Preparation 2022 and Onwards (Unit: Electrostatics : Set-1 (30 MCQs)) for National MDCAT, ECAT, FPSC, PPSC, JOB Exam, Physics Lecturer, SSC, HSSC (F.Sc.), BS, MS Exams NTS, ETS, etc..
1. The electrostatic force between two point charges is independent of one of the following quantities
F = `\frac {1}{4ㅈƐ_0}``\frac {q_1q_2}{r^2}`
2. If the distance between two equal charges is reduced to half and the magnitude of charges is also decreased to half, then the force between them will be
F = `\frac {1}{4ㅈƐ_0}``\frac {q_1q_2}{r^2}`
3. The concept of the electric field was introduced by
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4. The number of electrons or protons which constitutes a charge of one coulomb is
1 C of charge is contained in `\frac {1}{1.6 x 10^{-19}}`= 6.25 x 10¹⁸. Therefore, 6 x 10¹⁸ electrons constitute one coulomb of charge.
5. For static electricity the value of relative permittivity is always
`\Ɛ_r` = `\frac {Ɛ}{Ɛ_0}` is always greater than one for all material (for vacuum its value is 1).
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P =qd
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ዋ = E ΔA cos ፀ
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The dimension of an electric potential is [M¹ L² T-³ I⁻¹], work is [M¹ L² T-²] and q is [T-¹ I¹]
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Answer is A. Energy `\Ɛ_r` = `\frac {Ɛ}{Ɛ_0}` is always greater than one for all material (for vacuum its value is 1).
6. A metallic charged sphere is placed in uniform electric field E, the electric field inside the sphere will be
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7. The electric intensity E at a point in a field due to a dipole depends upon distance 'r' the relationship between them is :
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8. The dipole moment is defined as the product of
P =qd
9. Debye is the unit of
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10. The electric flux is maximum when the angle 'θ' between the area vector and electric intensity is
ዋ = E ΔA cos ፀ
11. Electric flux is independent of one of the following quantities.
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12. The dimension of electric potential is the same as that of
The dimension of an electric potential is [M¹ L² T-³ I⁻¹], work is [M¹ L² T-²] and q is [T-¹ I¹]
13. Electron volt is the unit of
One electron volt (1 eV) equals 1.602 × 10−12 erg or 1.602 × 10−19 joule.
14. The energy of an electron which accelerates through a potential difference of 1000 V is
Energy gained by electron = V e = 1000 Vx1.6 x10⁻¹⁹ J = 1.6 x10⁻¹⁶ J
15. The unit of surface charge density is
σ = `\frac {q}{A}`
16.. Capacitance of a capacitor does not depend upon
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17. In the presence of dielectric material, the electric field between the plates of the capacitor will be :
The strength of the electric field is reduced due to the presence of a dielectric.
18. When the potential difference across the capacitor is decreased by dielectric then the capacitance of the capacitor will be
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19. The unit of the product of resistance and capacitance is equal to a unit of
Resistance x Capacitance = `\V/I x q/V` = `\q/I` = t
20. A capacitor is approximately full charged after
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21. The electric potential between two points A and B are ΔV. The work done W by the field in moving a charge from A to B is
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22. Two parallel metal plates are 8.00 m apart. The electric field between the plates is uniform, directed toward the right, and has a magnitude of 4.00 N/C. If an ion of charge +2e is released at rest at the left-hand plate, what is its kinetic energy when it reaches the right-hand plate?
🛆 K.E = q 🛆V where 🛆V = E. 🛆r So 🛆 K.E = q (E. 🛆r) = 2e x 4 N/C x 8 m = 64 eV
23. In the figure below, the charge on the 3 µF capacitors is
Using Q = Ce V and Ce = 1/C1 +1/C2 + 1/C3 -------In book options are given in F (farad) which is incorrect because we are asked to find Charge so replace F with C.
24. A microfarad capacitor of a TV is subjected to a 4000 V potential difference. The energy stored in the capacitor is
using formula U = 1/2 CV²
25. The electric flux through the surface of a sphere due to a charge q placed at its centre depends upon
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Gauss's law ф = Q /ε₀ Cube has 6 face For one face ф = (1/6)(Q /ε₀) = q/6ε₀
E = `\ frac{Kq}{r^2}` by putting values we get E = 4.5x10⁵ All the options given in the are wrong so replace anyone let option A with 4.5x10⁵ N
--------🛆U = 🛆 K.E = q 🛆V when q = 1 e ans 🛆V = 1 kV so 🛆 K.E = 1 keV
Volt/metre, newton/Coulomb and (Joule/ Coulomb).metre are all units of E, So replace it with all of these.
E = 🛆V/🛆A -- inside the conductor E = 0 ----🛆V = 0 V₂ = V₁
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26. An electric charge q is placed at the centre of a cube of the side "a". The electric flux on its one side will be
Gauss's law ф = Q /ε₀ Cube has 6 face For one face ф = (1/6)(Q /ε₀) = q/6ε₀
27. The electric field at a distance of 20 cm from 2 µC charges is: :
E = `\ frac{Kq}{r^2}` by putting values we get E = 4.5x10⁵ All the options given in the are wrong so replace anyone let option A with 4.5x10⁵ N
28. A proton is about 1840 times heavier than an electron. When accelerated by a potential difference if 1 kV, it's kinetic energy will be:
--------🛆U = 🛆 K.E = q 🛆V when q = 1 e ans 🛆V = 1 kV so 🛆 K.E = 1 keV
29. The unit of Electric field intensity is :
Volt/metre, newton/Coulomb and (Joule/ Coulomb).metre are all units of E, So replace it with all of these.
30. Some charge is given to a conductor. Then it's potential
E = 🛆V/🛆A -- inside the conductor E = 0 ----🛆V = 0 V₂ = V₁
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© 2022-Onwards by Academic Skills and Knowledge (ASK)
Note: Write to me in the comment box below for any query and also Share this information with your class-fellows and friends.
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