A morning walker completes one lap on a 628 m-long circular track. If the beginning and ending positions are the same, calculate the distance and displacement he traveled. Determine his average speed and average velocity after he completed the trip in 2 minutes.

Ans {628 m, 0 m, 5.233 m/s, and 0 m/s }


Data Given:


Length of the circular track = s = 628 m

time = t = 2 min = 120 sec

Initial Position = Final position


To Find:


distance = s = ?

displacement = `\vec d` = ?

Average speed = `v_{ave}` = ?

Average speed = `vec v_{ave}` = ?

Solution:  

Distance:
The length of the path between two positions is called distance. So the length of the track is the covered distance = s = 628 m ----Ans.1


Displacement:
The shortest distance from the initial position to the final position (straight directed distance) is called displacement. As we are given that the beginning (initial) and ending (final) positions are the same.  So the shortest distance or displacement = `\vec d` = 0 m ----Ans.2



Average Speed:
Average speed is the total distance "s" covered in total time "t". Mathematically:

`\v_{ave}` = `\frac {s}{t}`

by putting values

`\v_{ave}` = `\frac {628 m}{120 s}` = 5.233 m/s----Ans.3



Average Velocity:
Average speed is the total displacement "`\vec d`" covered in total time "t". Mathematically:

`\vec v_{ave}` = `\frac {vec d}{t}`

by putting values

`\vec v_{ave}` = `\frac {0 m}{120 s}` = 0 m/s -------Ans.4




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