Physics SSC - I (Class 9) - Numerical Problem No. 6, Unit-2: Kinematics (National Book Foundation 2022 as Federal Text Book, Islamabad)

Consider the following speed time graph. Tell:
a. Which part of the graph is showing acceleration, deceleration, and zero acceleration?
b. Calculate the covered distance from 10 seconds to 20 seconds from the graph 

Ans {Line OA, Line BC, Line AB, 500 m }

a. Which part of the graph is showing acceleration, deceleration, and zero acceleration?

Answer:

Acceleration = Line OA

Deceleration = Line BC

Zero Acceleration = Line AB

b. Calculate the covered distance from 10 seconds to 20 seconds from the graph 

Given Data:

Time (from 10 to 20 s) = t = 10 s

Speed = v = 50 m/s

To Find:

Distance covered = S = ?

Solution:  

By using the equation

S = v_ave ｘ t

by putting values

S = 50 m s⁻¹ + 10 s

S = 500 m ----------- Ans.

************************************

Shortcut Links For 

1. Class 9 Physics SLO Based Combined Notes
2. Class 9 Physics MCQs Quizzes All Units
3. Class 10 Physics SLO Based Combined Notes
4. Class 10 Physics MCQs Quizzes All Units

1. Website for School and College Level Physics   

(https://askrarequiz.blogspot.com)

2. Website for School and College Level Mathematics  

(https://askraremaths.blogspot.com)

3. Website for Single National Curriculum Pakistan - All Subjects Notes 

(https://askrareclassnotes.blogspot.com/)

© 2020-21 Academic Skills and Knowledge (ASK)     

Note:  Write me in the comments box below for any query and also Share this information with your class-fellows and friends.