The speed v of sound waves through a medium may be assumed to depend on (a) the density 𝝆 of the medium and (b) its modulus of elasticity E which is the ratio of stress to strain. Deduce by the method of dimensions, the formula for the speed of sound.


(Ans: v = E )

Given:

Speed of sound depends on
𝝆 = density of the medium
E = Modulus of elasticity = stress : strain

To Find:

To deduce the formula for the speed of sound by the method of dimensions = v = ? 


Solution:

According to the given conditions, the formula for the speed (v) of sound will be

v ∝ a Eb

or

v = Constant a Eb  ------Equation (a)

Now using dimensions methods we will find the values of power a and b.

R.H.S. Dimensions of the equation (1):

[v] = [LT⁻¹]

L.H.S. Dimensions of the equation (1):

[] = [ML⁻³]

[E] = [ML⁻¹T⁻²] 
 
(∴ E = Stress / Strain  --- Stress = Force/Area and Strain = Change in Volume / Volume)

Now writing the dimension of both sides of the equation (1) we get

[LT⁻¹] = [ML³]a [ML¹T²]b

By separating each dimension quantity both side

[L] [T]⁻¹ = [M]a+b [L]-3a-b [T]-2b

Now equating the power (exponent) of [M], [L], and [T] on both side, we get

By equating the powers (exponents) of  [M]
0 = a + b    ----- eqn (i)

By equating the powers  of  [L]
1 = -3a - b    ----- eqn (ii)

By equating the powers of  [T]
-1 = -2b    ----- eqn (iii)

From eqn (i) we get

b = 12 

and substituting the value of b in eqn (i) or (ii) we get

a = -12

Now substituting the values of a and b in Equation (a) we have

v = Constant -12 E12

vConstant E1212

v Constant (E)12

or

vConstant E   --------Ans

Hence, the required formula for the speed of sound


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