The torque or turning effect of force about a given point is given by r x F where r is the vector from the given point to the point of application of F. Consider a force F = - 3 Ë†iˆi + ˆjˆj +5ˆkˆk (newton) acting on the point 7ˆiˆi + 3 ˆjˆj + ˆkˆk (m). What is the torque in N m about the origin?


(Ans: 14ˆiˆi -38 Ë†jˆj +16ˆkˆk Nm ]

Given:

Force = →F→F = -3ˆiˆi + ˆjˆj + 5ˆkˆk Newton
Position Vector = →r→r 7ˆiˆi + 3ˆjˆj + ˆkˆk  meters

To Find:

Torque = T = ?

Solution: 

We know that 

T→r→r x â†’F→F 

by putting values

T = â†’r→r x â†’F→F  = (-3ˆiˆi + ˆjˆj + 5ˆkˆk)x (7ˆiˆi + 3ˆjˆjˆkˆk)  Nm

Cross product of two vectors can be solved by writing determinant method and then expanding


T = â†’r→r x â†’F→F Ë†i(15 - 1) - ˆj (35 + 3) + ˆi(7 +9)


T = â†’r x â†’F  = 14ˆi - 38ˆj + 16 ˆi Nm  ----- Ans



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