The torque or turning effect of force about a given point is given by r x F where r is the vector from the given point to the point of application of F. Consider a force F = - 3 ˆiˆi + ˆjˆj +5ˆkˆk (newton) acting on the point 7ˆiˆi + 3 ˆjˆj + ˆkˆk (m). What is the torque in N m about the origin?
(Ans: 14ˆiˆi -38 ˆjˆj +16ˆkˆk Nm ]
Given:
Force = →F→F = -3ˆiˆi + ˆjˆj + 5ˆkˆk NewtonPosition Vector = →r→r = 7ˆiˆi + 3ˆjˆj + ˆkˆk meters
To Find:
Torque = T = ?
Solution:
We know that
T = →r→r x →F→F
by putting values
T = →r→r x →F→F = (-3ˆiˆi + ˆjˆj + 5ˆkˆk)x (7ˆiˆi + 3ˆjˆj + ˆkˆk) Nm
Cross product of two vectors can be solved by writing determinant method and then expanding

T = →r→r x →F→F = ˆi(15 - 1) - ˆj (35 + 3) + ˆi(7 +9)
T = →r x →F = 14ˆi - 38ˆj + 16 ˆi Nm ----- Ans
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Numerical Problem 2.12 ⇑ |
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